A sphere of radius R has a uniform distributi | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) Let sphere has uniform chare density $\rho \,\left( { = \frac{{3Q}}{{4\pi {R^3}}}} \right)$ and $E$ is the electric field at distance $x$ from the

Vedclass · Accepted Answer

$x$

Vedclass · Answer

(c) Let sphere has uniform chare density $ho \,\left( { = \frac{{3Q}}{{4\pi {R^3}}}} ight)$ and $E$ is the electric field at distance $x$ from the centre of the sphere.
Applying Gauss law
$E.\,4\pi \,{x^2} = \frac{q}{{{\varepsilon _0}}} = \frac{{ho V'}}{{{\varepsilon _0}}} = \frac{ho }{{{\varepsilon _0}}} 	imes \frac{4}{3}\pi {x^3}$
($V' = $ Volume of dotted sphere)
 $E = \frac{ho }{{3{\varepsilon _0}}}x$ $==>$ $E \propto \,x$

A sphere of radius $R$ has a uniform distribution of electric charge in its volume. At a distance $x$ from its centre, for $x < R$, the electric field is directly proportional to

Similar Questions

According to Gauss’ Theorem, electric field of an infinitely long straight wire is proportional to

The electric field $\vec E = {E_0}y\hat j$ acts in the space in which a cylinder of radius $r$ and length $l$ is placed with its axis parallel to $y-$ axis. The charge inside the volume of cylinder is

A hollow insulated conducting sphere is given a positive charge of $10\,\mu \,C$. ........$\mu \,C{m^{ - 2}}$ will be the electric field at the centre of the sphere if its radius is $2$ meters

A long, straight wire is surrounded by a hollow, thin, long metal cylinder whose axis coincides with that of wire. The wire has a charge per unit length of $\lambda$, and the cylinder has a net charge per unit length of $2\lambda$. Radius of the cylinder is $R$

$\sigma$ is the uniform surface charge density of a thin spherical shell of radius $R$. The electric field at any point on the surface of the spherical shell is: