Three particles of masses 10g, 20g and 40g&nb | vedclass

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Question

From conservation of momentum,

$\mathrm{m}_{1} \overrightarrow{\mathrm{u}}_{1}+\mathrm{m}_{2} \overrightarrow{\mathrm{u}}_{2}+\mathrm{m}_{3} \overr

Vedclass · Accepted Answer

$\widehat i + 3\widehat j + 10\widehat k\,\,$

Vedclass · Answer

From conservation of momentum,

$\mathrm{m}_{1} \overrightarrow{\mathrm{u}}_{1}+\mathrm{m}_{2} \overrightarrow{\mathrm{u}}_{2}+\mathrm{m}_{3} \overrightarrow{\mathrm{u}}_{3}=\mathrm{m}_{1} \overrightarrow{\mathrm{v}}_{1}+\mathrm{m}_{2} \overrightarrow{\mathrm{v}}_{2}+\mathrm{m}_{3} \overrightarrow{\mathrm{v}}_{3}$

$10(10 \hat{\mathrm{i}})+20(10 \hat{\mathrm{j}})+40(10 \hat{\mathrm{k}})$

$=10(0)+20(3 \hat{\mathrm{i}}+4 \hat{\mathrm{j}})+40 \overrightarrow{\mathrm{v}}_{3}$

$\Rightarrow 40 \overrightarrow{\mathrm{V}}_{3}=40 \mathrm{i}+120 \mathrm{j}+400 \hat{\mathrm{k}}$

$\overrightarrow{\mathrm{v}}_{3}=\hat{\mathrm{i}}+3 \hat{\mathrm{j}}+10 \hat{\mathrm{k}}$

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