2.Motion in Straight Line
medium

A stone thrown upward with a speed $u$ from the top of the tower reaches the ground with a velocity $3u$. The height of the tower is

A

$3{u^2}/g$

B

$4{u^2}/g$

C

$6{u^2}/g$

D

$9{u^2}/g$

Solution

(b)${v^2} = {u^2} + 2gh$ $ \Rightarrow {(3u)^2} = {( – u)^2} + 2gh \Rightarrow h = \frac{{4{u^2}}}{g}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.