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2.Motion in Straight Line
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A stone thrown upward with a speed $u$ from the top of the tower reaches the ground with a velocity $3u$. The height of the tower is
A
$3{u^2}/g$
B
$4{u^2}/g$
C
$6{u^2}/g$
D
$9{u^2}/g$
Solution
(b)${v^2} = {u^2} + 2gh$ $ \Rightarrow {(3u)^2} = {( – u)^2} + 2gh \Rightarrow h = \frac{{4{u^2}}}{g}$
Standard 11
Physics
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