3-2.Motion in Plane
easy

A stone tied to $180 cm$ long string at its end is making 28 revolutions in horizontal circle in every minute. The magnitude of acceleration of stone is $\frac{1936}{ x }\,ms ^{-2}$. The value of $x.........\left(\text { Take } \pi=\frac{22}{7}\right)$

A$124$
B$123$
C$125$
D$122$
(JEE MAIN-2023)

Solution

$a=\omega^2 R=\left(\frac{28 \times 2 \pi}{60}\right)^2 \times 1.8$
$=\left(\frac{56}{60} \times \frac{22}{7}\right)^2 \times 1.8$
$=\frac{(44)^2}{225} \times 1.8$
$=\frac{1936 \times 1.8}{225}$
$x=125$
Standard 11
Physics

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