- Home
- Standard 11
- Physics
3-2.Motion in Plane
easy
A stone tied to $180 cm$ long string at its end is making 28 revolutions in horizontal circle in every minute. The magnitude of acceleration of stone is $\frac{1936}{ x }\,ms ^{-2}$. The value of $x.........\left(\text { Take } \pi=\frac{22}{7}\right)$
A$124$
B$123$
C$125$
D$122$
(JEE MAIN-2023)
Solution
$a=\omega^2 R=\left(\frac{28 \times 2 \pi}{60}\right)^2 \times 1.8$
$=\left(\frac{56}{60} \times \frac{22}{7}\right)^2 \times 1.8$
$=\frac{(44)^2}{225} \times 1.8$
$=\frac{1936 \times 1.8}{225}$
$x=125$
$=\left(\frac{56}{60} \times \frac{22}{7}\right)^2 \times 1.8$
$=\frac{(44)^2}{225} \times 1.8$
$=\frac{1936 \times 1.8}{225}$
$x=125$
Standard 11
Physics
Similar Questions
hard