A student is standing at a distance of 50,met | vedclass

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Question

(c) Let student will catch the bus after $t \,sec$. So it will cover distance $ut$.
Similarly distance travelled by the bus will be $\frac{1}{2}a{t^2

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(c) Let student will catch the bus after $t \,sec$. So it will cover distance $ut$.
Similarly distance travelled by the bus will be $\frac{1}{2}a{t^2}$ for the given condition
$ut = 50 + \frac{1}{2}a{t^2} = 50 + \frac{{{t^2}}}{2}$  [$a = 1\;m/{s^2}$]
$&rArr;$ $ u  = \frac{{50}}{t} + \frac{t}{2}$
To find the minimum value of $u$
$\frac{{du}}{{dt}} = 0$, so we get $t = 10\sec $, then $u = 10\;m/s$

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