A tangent to the circle ${x^2} + {y^2} = 5$at the point $(1,-2)$ the circle ${x^2} + {y^2} - 8x + 6y + 20 = 0$
A tangent to the circle ${x^2} + {y^2} = 5$at the point $(1,-2)$ the circle ${x^2} + {y^2} - 8x + 6y + 20 = 0$
- [IIT 1975]
- A
Touches
- B
Cuts at real points
- C
Cuts at imaginary points
- D
None of these
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- [KVPY 2017]
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