Gujarati
Hindi
10-1.Thermometry, Thermal Expansion and Calorimetry
medium

A tap supplies water at $10\,^oC$ and another tap at $100\,^oC$. .......... $kg$ hot water must be taken so that we get $20\, kg$ water at $35\,^oC$ ?

A

$7.2$

B

$10$

C

$5.6$

D

$14.4$

Solution

Let $\mathrm{x}$ $kg$ hot water required

heat lost$=$ heat gain

$\mathrm{xs}(100-35)=(20-\mathrm{x}) \mathrm{s}(35-10)$

$\Rightarrow 65 \mathrm{x}=(20-\mathrm{x}) \times 2 \mathrm{s}$

$\Rightarrow 90 \mathrm{x}=500 \Rightarrow \mathrm{x}=\frac{50}{9}=5.55 \mathrm{kg}$

Standard 11
Physics

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