- Home
- Standard 11
- Physics
10-1.Thermometry, Thermal Expansion and Calorimetry
medium
A tap supplies water at $10\,^oC$ and another tap at $100\,^oC$. .......... $kg$ hot water must be taken so that we get $20\, kg$ water at $35\,^oC$ ?
A
$7.2$
B
$10$
C
$5.6$
D
$14.4$
Solution
Let $\mathrm{x}$ $kg$ hot water required
heat lost$=$ heat gain
$\mathrm{xs}(100-35)=(20-\mathrm{x}) \mathrm{s}(35-10)$
$\Rightarrow 65 \mathrm{x}=(20-\mathrm{x}) \times 2 \mathrm{s}$
$\Rightarrow 90 \mathrm{x}=500 \Rightarrow \mathrm{x}=\frac{50}{9}=5.55 \mathrm{kg}$
Standard 11
Physics
Similar Questions
hard