1.Units, Dimensions and Measurement
medium

A travelling microscope is used to determine the refractive index of a glass slab. If $40$ divisions are there in $1 \; cm$ on main scale and $50$ Vernier scale divisions are equal to $49$ main scale divisions, then least count of the travelling microscope is $\dots \; \times 10^{-6} \; m$

A

$2$

B

$3$

C

$4$

D

$5$

(JEE MAIN-2022)

Solution

$50 \; VSD =49 \; MSD$

$1 \; VSD =\frac{49}{50} \; MSD$

Least count $=1 MSD -1 VSD$

$=\left(1-\frac{49}{50}\right) MSD =\frac{1}{50} \; MSD$

$1 \; MSD =\frac{1}{40} \; cm$

Least count $=\frac{1}{50 \times 40} \; cm$

$=\frac{1}{2000} cm =\frac{1}{2} \times 10^{-5} \; m$

$=0.5 \times 10^{-5} \; m$

$=5 \times 10^{-6} \; m$

Standard 11
Physics

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