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14.Waves and Sound
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A tuning fork of frequency $480 Hz$ produces $10$ beats per second when sounded with a vibrating sonometer string. What must have been the frequency of the string if a slight increase in tension produces lesser beats per second than before ..... $Hz$
A
$460$
B
$470$
C
$480$
D
$490$
Solution
(b) If suppose $n_S$ = frequency of string $ = \frac{1}{{2l}}\sqrt {\frac{T}{m}} $
$n_f$ = Frequency of tuning fork $= 480 Hz$
$x =$ Beats heard per second $= 10$
as tension $T$ increases, so $ n_S$ increases ($\uparrow$)
Also it is given that number of beats per sec decreases (i.e. $x\downarrow$)
Hence $ n_S\uparrow -n_f = x\downarrow$ … $(i)$ $\rightarrow$ Wrong
$n_f -nS\uparrow = x\downarrow$ … $(ii)$ $\rightarrow$ Correct
$\Rightarrow$ $n_S = n_f -x = 480 -10 = 470 Hz.$
Standard 11
Physics
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