A tunnel is dug along a diameter of earth. If Mₑ and Rₑ are mass and radius of earth respectivel

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7.Gravitation

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A tunnel is dug along a diameter of the earth. If $M_e$ and $R_e$ are the mass and radius of the earth respectively. Then the force on a particle of mass $'m'$ placed in the tunnel at a distance $r$ from the centre is

A

$\frac{{G{M_e}m}}{{R_e^3}}.r$

B

$\frac{{G{M_e}}}{{R_e^3}}.\frac{m}{r}$

C

$\frac{{G{M_e}m}}{r}.R_e^3$

D

$\frac{{G{M_e}m}}{{R_e^2}}.r$

Solution

$\mathrm{F}=\frac{\mathrm{GM}^{1} \mathrm{m}}{\mathrm{r}^{2}}$

$\mathrm{M}^{1}=\frac{\mathrm{GMe}}{\mathrm{Re}^{3}} \times \mathrm{r}^{3}$

$\mathrm{F}_{\text {attaction }}=\frac{\text { GMeM }}{\mathrm{Re}^{3}} \times \mathrm{r}$

Standard 11

Physics

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