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2. Electric Potential and Capacitance
easy
A uniform electric field having a magnitude ${E_0}$ and direction along the positive $X - $ axis exists. If the potential $V$ is zero at $x = 0$, then its value at $X = + x$ will be
A
${V_{x}} = + x{E_0}$
B
${V_x} = - x{E_0}$
C
${V_x} = + {x^2}{E_0}$
D
${V_x} = - {x^2}{E_0}$
Solution
(b) $==>$ ${V_x} = – x{E_0}$
Standard 12
Physics