A vector overrightarrow A points vertically upward and overrightarrow B points towards north. vector

English

Gujarati

Hindi

3-1.Vectors

medium

A vector $\overrightarrow A $ points vertically upward and $\overrightarrow B $points towards north. The vector product $\overrightarrow A \times \overrightarrow B $ is

A

Zero

B

Along west

C

Along east

D

Vertically downward

Solution

(b) Direction of vector $A$ is along $Z-a$axis $⇒$ $\vec A = a\hat k$

Direction of vector $B$ is towards north $⇒$ $\vec B = b\hat j$

Now $\vec A \times \vec B = a\hat k \times b\hat j = ab( – \hat j)$

$\therefore$ The direction is $\vec A \times \vec B$ is along west.

Standard 11

Physics

Share

Similar Questions

Write the necessary condition for the scalar product of two mutually perpendicular vectors.

medium

If for two vector $\overrightarrow A $ and $\overrightarrow B $, sum $(\overrightarrow A + \overrightarrow B )$ is perpendicular to the difference $(\overrightarrow A – \overrightarrow B )$. The ratio of their magnitude is

hard

Dot product of two mutual perpendicular vector is

easy

The position vectors of points $A, B, C$ and $D$ are $A = 3\hat i + 4\hat j + 5\hat k,\,\,B = 4\hat i + 5\hat j + 6\hat k,\,\,C = 7\hat i + 9\hat j + 3\hat k$ and $D = 4\hat i + 6\hat j$ then the displacement vectors $AB$ and $CD $ are

medium

Show that $a \cdot( b \times c )$ is equal in magnitude to the volume of the parallelepiped formed on the three vectors, $a, b$ and $c$.

medium