A vector in x-y plane makes an angle of 30^{c | vedclass

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Question

$A _y= A \cos 30^{\circ}=2 \sqrt{3}$

$\Rightarrow A \frac{\sqrt{3}}{2}=2 \sqrt{3}$

$\Rightarrow A =4$

Now $A_x=A \sin 30^{\circ}=4 	imes \fr

Vedclass · Accepted Answer

$2$

Vedclass · Answer

$A _y= A \cos 30^{\circ}=2 \sqrt{3}$

$\Rightarrow A \frac{\sqrt{3}}{2}=2 \sqrt{3}$

$\Rightarrow A =4$

Now $A_x=A \sin 30^{\circ}=4 	imes \frac{1}{2}=2$

A vector in $x-y$ plane makes an angle of $30^{\circ}$ with $y$-axis The magnitude of $y$-component of vector is $2 \sqrt{3}$. The magnitude of $x$-component of the vector will be

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