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8.Mechanical Properties of Solids
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A wire of cross-sectional area $3\,m{m^2}$ is first stretched between two fixed points at a temperature of $20°C$. Determine the tension when the temperature falls to $10°C$. Coefficient of linear expansion $\alpha = {10^{ - 5}} { ^\circ}{C^{ - 1}}$ and $Y = 2 \times {10^{11}}\,N/{m^2}$ ........ $N$
A
$20 $
B
$30$
C
$60$
D
$120$
Solution
(c) $F = YA\alpha \Delta t$$ = 2 \times {10^{11}} \times 3 \times {10^{ – 6}} \times {10^{ – 5}} \times (20 – 10) = 60\,N$
Standard 11
Physics
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