A wire of length $L\, (=20\, cm)$, is bent into a semicircular arc. If the two equal halves of the arc were each to be uniformly charged with charges $ \pm Q\,,\,\left[ {\left| Q \right| = {{10}^3}{\varepsilon _0}} \right]$ Coulomb where $\varepsilon _0$ is the permittivity (in $SI\, units$) of free space] the net electric field at the centre $O$ of the semicircular arc would be
$\left( {50 \times {{10}^3}\,N/C} \right)\hat j$
$\left( {50 \times {{10}^3}\,N/C} \right)\hat i$
$\left( {25 \times {{10}^3}\,N/C} \right)\hat j$
$\left( {25 \times {{10}^3}\,N/C} \right)\hat i$
The electric field due to a charge at a distance of $3\, m$ from it is $500\, N/coulomb$. The magnitude of the charge is.......$\mu C$ $\left[ {\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {{10}^9}\,\frac{{N - {m^2}}}{{coulom{b^2}}}} \right]$
In the following four situations charged particles are at equal distance from the origin. Arrange them the magnitude of the net electric field at origin greatest first
The point charges $Q$ and $-2Q$ are placed at some distance apart. If the electric field at the location of $Q$ is $\vec E$ , then the electric field at the location of $-2Q$ will be :
Infinite charges of magnitude $q$ each are lying at $x =1,\, 2,\, 4,\, 8...$ meter on $X$-axis. The value of intensity of electric field at point $x = 0$ due to these charges will be
The magnitude of electric field intensity $E$ is such that, an electron placed in it would experience an electrical force equal to its weight is given by