A wooden block of mass $M$ is suspended by a cord and is at rest. A bullet of mass $m,$ moving with a velocity $v$ passes through the block and comes out with a velocity $v/2$ in the same direction. If there is no loss in kinetic energy, then upto what height the block will rise
${m^2}{v^2}/2{M^2}g$
${m^2}{v^2}/8{M^2}g$
${m^2}{v^2}/4Mg$
${m^2}{v^2}/2Mg$
Masses of two substances are $1\, g$ and $9\, g$ respectively. If their kinetic energies are same, then the ratio of their momentum will be
A block of mass $0.50\ kg$ is moving with a speedof $2.00$ $ms^{-1}$ on a smooth surface. It strikes another mass of $1.00\ kg$ and then they move together as a single body. The energy loss during the collision is ............. $\mathrm{J}$
Three bodies $A, B$ and $C$ have equal kinetic energies and their masses are $400 \mathrm{~g}, 1.2 \mathrm{~kg}$ and $1.6 \mathrm{~kg}$ respectively. The ratio of their linear momenta is :
Four particles $A, B, C, D$ of mass $\frac{\mathrm{m}}{2}, \mathrm{~m}, 2 \mathrm{~m}, 4 \mathrm{~m}$, have same momentum, respectively. The particle with maximum kinetic energy is:
Two solids $A$ and $B$ of mass $1\, kg$ and $2\, kg$ respectively are moving with equal linear momentum. The ratio of their kinetic energies $(K.E.)_{ A }:( K.E. )_{ B }$ will be $\frac{ A }{1},$ so the value of $A$ will be ..... .