13.Nuclei
easy

After $3$ hours, only $0.25 \,mg$ of a pure radioactive material is left. If initial mass was $2 \,mg$ then the half life of the substance is ...... $hr$

A

$1.5$

B

$1$

C

$0.5$

D

$2$

Solution

(b)

Initial mass $=2 \,mg$

Final mass $=0.25 \,mg$

$\therefore \frac{N}{N_0}=\left(\frac{1}{2}\right)^n$

$\frac{0.25}{2}=\left(\frac{1}{2}\right)^n$

$\frac{1}{8}=\left(\frac{1}{2}\right)^n$

$\therefore n=3$ and time is $3$ hours

Half life is therefore $1$ hour

Standard 12
Physics

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