Although $CN^-$ ion and $N_2$ molecule are isoelectronic, yet $N_2$ molecule is chemically inert because of
Although $CN^-$ ion and $N_2$ molecule are isoelectronic, yet $N_2$ molecule is chemically inert because of
- [AIEEE 2012]
- A
presence of more number of electrons in bonding orbitals
- B
lone bond energy
- C
absence of bond polarity
- D
uneven electron distribution
Similar Questions
Which of the following species would be expected paramagnetic
Which of the following species would be expected paramagnetic
What is chemical bonding ? How it is formed and give its types.
What is chemical bonding ? How it is formed and give its types.
What is the effect of the following processes on the bond order in $\mathrm{N}_{2}$ and $\mathrm{O}_{2}$ ?
$(A)$ ${{\rm{N}}_2} \to {\rm{N}}_2^ + + {{\rm{e}}^ - }$
$(B)$ ${{\rm{O}}_2} \to {\rm{O}}_2^ + + {{\rm{e}}^ - }$
What is the effect of the following processes on the bond order in $\mathrm{N}_{2}$ and $\mathrm{O}_{2}$ ?
$(A)$ ${{\rm{N}}_2} \to {\rm{N}}_2^ + + {{\rm{e}}^ - }$
$(B)$ ${{\rm{O}}_2} \to {\rm{O}}_2^ + + {{\rm{e}}^ - }$
The correct statement$(s)$ about $O _3$ is (are)
$(A)$ $O$ - $O$ bond lengths are equal.
$(B)$ Thermal decomposition of $O _3$ is endothermic.
$(C)$ $O _3$ is diamagnetic in nature.
$(D)$ $O _3$ has a bent structure.
The correct statement$(s)$ about $O _3$ is (are)
$(A)$ $O$ - $O$ bond lengths are equal.
$(B)$ Thermal decomposition of $O _3$ is endothermic.
$(C)$ $O _3$ is diamagnetic in nature.
$(D)$ $O _3$ has a bent structure.
- [IIT 2013]
Which is set of paramagnetic molecules or ions
Which is set of paramagnetic molecules or ions