An arbitrary surface encloses a dipole. electric flux through this surface ?

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1. Electric Charges and Fields

medium

An arbitrary surface encloses a dipole. What is the electric flux through this surface ?

Option A

Option B

Option C

Option D

Solution

According to Gauss's law, the flux associated with close surface is $\phi=\frac{\Sigma q}{\epsilon_{0}}$ where $q$ is charge enclosed by closed surface.

Net charge on dipole $=-q+q=0$

$\therefore$ Flux associated with closed surface enclosing dipole, $\phi=\frac{-q+q}{\epsilon_{0}}=0$

Standard 12

Physics

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Solution

Similar Questions

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