An arbitrary surface encloses a dipole. What is the electric flux through this surface ?
An arbitrary surface encloses a dipole. What is the electric flux through this surface ?
According to Gauss's law, the flux associated with close surface is $\phi=\frac{\Sigma q}{\epsilon_{0}}$ where $q$ is charge enclosed by closed surface.
Net charge on dipole $=-q+q=0$
$\therefore$ Flux associated with closed surface enclosing dipole, $\phi=\frac{-q+q}{\epsilon_{0}}=0$
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