An area of cross-section of rubber string is 2,c{m^2} . Its length is doubled when stretched with a

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8.Mechanical Properties of Solids

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An area of cross-section of rubber string is $2\,c{m^2}$. Its length is doubled when stretched with a linear force of $2 \times {10^5}$dynes. The Young's modulus of the rubber in $dyne/c{m^2}$ will be

A

$4 \times {10^5}$

B

$1 \times {10^5}$

C

$2 \times {10^5}$

D

$1 \times {10^4}$

Solution

(b) If length of the wire is doubled then strain $= 1$

Y = ${\rm{Stress}} = \frac{{{\rm{Force}}}}{{{\rm{Area}}}}$= $\frac{{2 \times {{10}^5}}}{2} = {10^5}\frac{{dyne}}{{c{m^2}}}$

Standard 11

Physics

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