An electromagnetic wave, going through vacuum | vedclass

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Question

(c)The angular wave number $k = \frac{{2\pi }}{\lambda };$ where $ \lambda$ is the wave length. The angular frequency is $w = 2\pi 
u .$
The ra

Vedclass · Accepted Answer

$k/ \omega$

Vedclass · Answer

(c)The angular wave number $k = \frac{{2\pi }}{\lambda };$ where $ \lambda$ is the wave length. The angular frequency is $w = 2\pi 
u .$
The ratio $\frac{k}{\omega } = \frac{{2\pi /\lambda }}{{2\pi 
u }} = \frac{1}{{
u \pi }} = \frac{1}{c}$= constant

An electromagnetic wave, going through vacuum is described by $E = {E_0}\sin (kx - \omega \,t)$. Which of the following is independent of wavelength

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