Consider an electromagnetic wave propagating in vacuum . Choose the correct statement
Consider an electromagnetic wave propagating in vacuum . Choose the correct statement
- [JEE MAIN 2016]
- A
For an electromagnetic wave propagating in $+y$ direction the electric field is $\vec E = \frac{1}{{\sqrt 2 }}\,{E_{yz}}\,\left( {x,t} \right)\,\hat z$ and the magnetic field is $\vec B = \frac{1}{{\sqrt 2 }}\,{B_z}\,\left( {x,t} \right)\hat y$
- B
For an electromagnetic wave propagating in $+y$ direction the electric field is $\vec E = \frac{1}{{\sqrt 2 }}\,{E_{yz}}\,\left( {x,t} \right)\,\hat y$ and the magnetic field is $\vec B = \frac{1}{{\sqrt 2 }}\,B_{yz}\,\left( {x,t} \right)\hat z$
- C
For an electromagnetic wave propagating in $+x$ direction the electric field is $\vec E = \frac{1}{{\sqrt 2 }}\,{E_{yz}}\,\left( {y,z,t} \right)\,\left( {\hat y + \hat z} \right)$ and the magnetic field is $\vec B = \frac{1}{{\sqrt 2 }}\,B_{yz}\,\left( {y,z,t} \right)\,\left( {\hat y + \hat z} \right)$
- D
For an electromagnetic wave propagating in $+x$ direction the electric field is $\vec E = \frac{1}{{\sqrt 2 }}\,{E_{yz}}\,\left( {x,t} \right)\,\left( {\hat y - \hat z} \right)$ and the magnetic field is $\vec B = \frac{1}{{\sqrt 2 }}\,B_{yz}\,\left( {x,t} \right)\,\left( {\hat y + \hat z} \right)$
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