A charged particle oscillates about its mean equilibrium position with a frequency of $10^9\ Hz$. The electromagnetic waves produced:

Suppose that the electric field part of an electromagnetic wave in vacuum is

$E =\left\{(3.1 \;N / C ) \text { cos }\left[(1.8 \;rad / m ) y+\left(5.4 \times 10^{6} \;rad / s \right) t\right]\right\} \hat{ i }$

$(a)$ What is the direction of propagation?

$(b)$ What is the wavelength $\lambda$ ?

$(c)$ What is the frequency $v ?$

$(d)$ What is the amplitude of the magnetic field part of the wave?

$(e)$ Write an expression for the magnetic field part of the wave.

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

$E _{ x }= E _0 \sin ( kz -\omega t )$

$B _{ y }= B _0 \sin ( kz -\omega t )$

Then the correct relation between $E_0$ and $B_0$ is given by

The direction of poynting vector represents

The electric field associated with an $e.m.$ wave in vacuum is given by $\vec E = \hat i\,40\,\cos \,\left( {kz – 6 \times {{10}^8}\,t} \right)$. where $E$, $z$ and $t$ are in $volt/m$, meter and seconds respectively. The value of wave factor $k$ is ……. $m^{-1}$.