8.Electromagnetic waves
medium

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

$E _{ x }= E _0 \sin ( kz -\omega t )$

$B _{ y }= B _0 \sin ( kz -\omega t )$

Then the correct relation between $E_0$ and $B_0$ is given by

A

$kE _0=\omega B _0$

B

$E _0 B _0=\omega k$

C

$\omega E _0= kB _0$

D

$E _0= kB _0$

(JEE MAIN-2023)

Solution

$C =\frac{\omega}{ k }=\frac{ E _0}{ B _0}$

Standard 12
Physics

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