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8.Electromagnetic waves
medium
The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by
$E _{ x }= E _0 \sin ( kz -\omega t )$
$B _{ y }= B _0 \sin ( kz -\omega t )$
Then the correct relation between $E_0$ and $B_0$ is given by
A
$kE _0=\omega B _0$
B
$E _0 B _0=\omega k$
C
$\omega E _0= kB _0$
D
$E _0= kB _0$
(JEE MAIN-2023)
Solution
$C =\frac{\omega}{ k }=\frac{ E _0}{ B _0}$
Standard 12
Physics
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