The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

$E _{ x }= E _0 \sin ( kz -\omega t )$

$B _{ y }= B _0 \sin ( kz -\omega t )$

Then the correct relation between $E_0$ and $B_0$ is given by

  • [JEE MAIN 2023]
  • A

    $kE _0=\omega B _0$

  • B

    $E _0 B _0=\omega k$

  • C

    $\omega E _0= kB _0$

  • D

    $E _0= kB _0$

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