An electron and a proton enter region of uniform magnetic field in a direction at right angles to fi

English

Gujarati

Hindi

4.Moving Charges and Magnetism

medium

An electron and a proton enter region of uniform magnetic field in a direction at right angles to the field with the same kinetic energy. They describe circular paths of radius ${r_e}$ and ${r_p}$ respectively. Then

${r_e} = {r_p}$

${r_e} < {r_p}$

${r_e} > {r_p}$

${r_e}$ may be less than or greater than ${r_p}$ depending on the direction of the magnetic field

Solution

(b) $r = \frac{{\sqrt {2mK} }}{{qB}}i.e.\;\;r \propto \frac{{\sqrt m }}{q}$
Here kinetic energy $K$ and $B$ are same.

$\therefore \;\frac{{{r_e}}}{{{r_p}}} = \sqrt {\frac{{{m_e}}}{{{m_p}}}} \times \frac{{{q_p}}}{{{q_e}}} \Rightarrow \frac{{{r_e}}}{{{r_p}}} = \sqrt {\frac{{{m_e}}}{{{m_p}}}} \;\;(\because \;{q_e} = {q_p})$
Since $m_e < m_p$, therefore $ r_e < r_p$

Standard 12

Physics

A particle of charge $q$ and mass $m$ is moving with a velocity $-v \hat{ i }(v \neq 0)$ towards a large screen placed in the $Y – Z$ plane at a distance $d.$ If there is a magnetic field $\overrightarrow{ B }= B _{0} \hat{ k },$ the minimum value of $v$ for which the particle will not hit the screen is

medium

(JEE MAIN-2020)

An electron emitted by a heated cathode and accelerated through a potential difference of $ 2.0 \;kV$, enters a region with uniform magnetic field of $0.15\; T$. Determine the trajectory of the electron if the field

$(a)$ is transverse to its initial velocity,

$(b)$ makes an angle of $30^o$ with the initial velocity

medium

Given below are two statements

Statement $I$ : The electric force changes the speed of the charged particle and hence changes its kinetic energy: whereas the magnetic force does not change the kinetic energy of the charged particle

Statement $II$ : The electric force accelerates the positively charged particle perpendicular to the direction of electric field. The magnetic force accelerates the moving charged particle along the direction of magnetic field. In the light of the above statements, choose the most appropriate answer from the options given below

medium

(JEE MAIN-2022)

If a charged particle goes unaccelerated in a region containing electric and magnetic fields

easy

A particle of specific charge (charge/mass) $\alpha$ starts moving from the origin under the action of an electric field $\vec E = {E_0}\hat i$ and magnetic field $\vec B = {B_0}\hat k$. Its velocity at $(x_0 , y_0 , 0)$ is ($(4\hat i + 3\hat j)$ . The value of $x_0$ is:

medium

An electron and a proton enter region of uniform magnetic field in a direction at right angles to the field with the same kinetic energy. They describe circular paths of radius ${r_e}$ and ${r_p}$ respectively. Then

Solution

Similar Questions

If a charged particle goes unaccelerated in a region containing electric and magnetic fields

A particle of specific charge (charge/mass) $\alpha$ starts moving from the origin under the action of an electric field $\vec E = {E_0}\hat i$ and magnetic field $\vec B = {B_0}\hat k$. Its velocity at $(x_0 , y_0 , 0)$ is ($(4\hat i + 3\hat j)$ . The value of $x_0$ is:

Start a Free Trial Now