An ellipsoidal cavity is carved within a perfect conductor. A positive charge $q$ is placed at the centre of the cavity. The points $A$ and $B$ are on the cavity surface as shown in the figure. Then
An ellipsoidal cavity is carved within a perfect conductor. A positive charge $q$ is placed at the centre of the cavity. The points $A$ and $B$ are on the cavity surface as shown in the figure. Then
- [IIT 1999]
- A
Electric field near $A$ in the cavity = Electric field near $B$ in the cavity
- B
Total electric field flux through the surface of the cavity is $q/{\varepsilon _0}$
- C
Potential at $A = $ Potential at $B$
- D
Both $(b)$ and $(c)$
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- [JEE MAIN 2020]
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- [IIT 2024]