How much electric flux will come out through a surface S = 10hat{j} kept in an electrostatic field v

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1. Electric Charges and Fields

easy

How much electric flux will come out through a surface $S = 10\hat j$ kept in an electrostatic field $\vec E = 2\hat i + 4\hat j + 7\hat k$.........$units$

A

$20$

B

$40$

C

$70$

D

$80$

Solution

$ \phi =\overrightarrow{\mathrm{E}} \overrightarrow{\mathrm{S}} $

$=(2 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}+7 \hat{\mathrm{k}}) \cdot 10 \hat{\mathrm{j}}=40\, \text { units } $

Standard 12

Physics

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