An oil drop having charge $2e$ is kept stationary between two parallel horizontal plates $2.0\, cm$ apart when a potential difference of $12000\, volts$ is applied between them. If the density of oil is $900 \,kg/m^3$, the radius of the drop will be
$2.0 \times {10^{ - 6}}\,m$
$1.7 \times {10^{ - 6}}\,m$
$1.4 \times {10^{ - 6}}\,m$
$1.1 \times {10^{ - 6}}\,m$
Equipotential surfaces are shown in figure. Then the electric field strength will be
In a certain region of space, variation of potential with distance from origin as we move along $x$-axis is given by $V=8 x^2+2$, where $x$ is the $x$-coordinate of a point in space. The magnitude of electric field at a point $(-4,0)$ is .......... $V / m$
The potential (in volts ) of a charge distribution is given by
$V(z)\, = \,30 - 5{z^2}for\,\left| z \right| \le 1\,m$
$V(z)\, = \,35 - 10\,\left| z \right|for\,\left| z \right| \ge 1\,m$
$V(z)$ does not depend on $x$ and $y.$ If this potential is generated by a constant charge per unit volume $\rho _0$ (in units of $\varepsilon _0$ ) which is spread over a certain region, then choose the correct statement
The electrostatic potential inside a charged spherical ball is given by $\phi= a{r^2} + b$ where $r$ is the distance from the centre and $a, b$ are constants. Then the charge density inside the ball is:
Two parallel plates separated by a distance of $5\,mm$ are kept at a potential difference of $50\,V.$ A particle of mass ${10^{ - 15}}\,kg$ and charge ${10^{ - 11}}\,C$ enters in it with a velocity ${10^7}\,m/s.$ The acceleration of the particle will be