An unbiased die is tossed until a number grea | vedclass

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Question

(b) Probability of success $ = \frac{2}{6} = \frac{1}{3} = p$

Probability of failure $ = 1 - \frac{1}{3} = \frac{2}{3} = q$

Probability that suc

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$\frac{2}{5}$

Vedclass · Answer

(b) Probability of success $ = \frac{2}{6} = \frac{1}{3} = p$

Probability of failure $ = 1 - \frac{1}{3} = \frac{2}{3} = q$

Probability that success occurs in even number of tosses

$ = P(FS) + P(FFFS) + P(FFFFFS) + ..........$

$ = pq + {q^3}p + {q^5}p + ........$

$ = \frac{{pq}}{{1 - {q^2}}} = \frac{2}{5}.$

An unbiased die is tossed until a number greater than $4$ appears. The probability that an even number of tosses is needed is

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