An unknown metal of mass 192, g heated to a temperature of 100,^oC was immersed into a brass calorim

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10-1.Thermometry, Thermal Expansion and Calorimetry

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An unknown metal of mass $192\, g$ heated to a temperature of $100\,^oC$ was immersed into a brass calorimeter of mass $128\, g$ containing $240\, g$ of water at a temperature of $8.4\,^oC$. Calculate the specific heat of the unknown metal if water temperature stabilizes at $21.5\,^oC$. (Specific heat of brass is $394\, J\, kg^{-1}\, K^{-1}$) ......... $J\, kg^{-1}\, K^{-1}$

A

$458$

B

$920$

C

$1232$

D

$654$

(JEE MAIN-2019)

Solution

$Heat\,loss = Heat\,gain$

$192 \times S\left( {100 – 21.5} \right)$

$ = \left( {128 \times 0.394 + 240 \times 4.2} \right)\left( {21.5 – 8.4} \right)$

$192 \times 78.5 \times S = 1058.432 \times 13.1$

$S = 0.91995\,J/g\,{K^{ – 1}}$

$S = 919.95\,J/kg\,{K^{ – 1}}$

Standard 11

Physics

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