Angular displacement (θ ) of a flywheel varies with time as θ = at + b{t^2} + c{t^3} then an

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3-2.Motion in Plane

easy

Angular displacement $(\theta )$ of a flywheel varies with time as $\theta = at + b{t^2} + c{t^3}$ then angular acceleration is given by

A

$a + 2bt - 3c{t^2}$

B

$2b - 6t$

C

$a + 2b - 6t$

D

$2b + 6ct$

Solution

(d) Angular acceleration $\alpha = \frac{{{d^2}\theta }}{{d{t^2}}} = \frac{{{d^2}}}{{d{t^2}}}(at + b{t^2} + c{t^3})$$ = 2b + 6ct$

Standard 11

Physics

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