6-2.Equilibrium-II (Ionic Equilibrium)
medium

If the $pKa$ of lactic acid is $5$,then the $pH$ of $0.005$ $M$ calcium lactate solution at $25^{\circ}\,C$ is $........\times 10^{-1}$ (Nearest integer)

A

$85$

B

$84$

C

$83$

D

$82$

(JEE MAIN-2023)

Solution

Concentration of calcium lactate $=0.005\,M ,:$ concentration of lactate ion $=(2 \times 0.005)\,M$. Calcium lactate is a salt of weak acid $+$ strong base $\therefore$ Salt hydrolysis will take place.

$pH =7+\frac{1}{2}( pKa +\log C )$

$=7+\frac{1}{2}(5+\log (2 \times 0.005))$

$=7+\frac{1}{2}[5-2 \log 10]=7+\frac{1}{2} \times 3=8.5=85 \times 10^{-1}$

Standard 11
Chemistry

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.