2. Electric Potential and Capacitance
easy

At a certain distance from a point charge the electric field is $500\,V/m$ and the potential is $3000\,V$. What is this distance......$m$

A$6$
B$12$
C$36$
D$144$

Solution

(a) $V = E \times \,r$ $==>$ $r = \frac{V}{E} = \frac{{3000}}{{500}} = 6\,m$
Standard 12
Physics

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