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- Quantitative Aptitude
At a village trade fair a man buys a horse and a camel together for $Rs.$ $51,250 .$ He sold the horse at a profit of $25 \%$ and the camel at a loss of $20 \% .$ If he sold both the animals at the same price, then the cost price of the cheaper animal was $Rs.$.........
$6600$
$7500$
$25000$
$20000$
Solution
cost of price of cheaper anlmal Is $Rs 20,000 .$
Let the cost price of horse be Rs a and cost price of camel be $\operatorname{Rs}(51250-a)$.
According to the question:
He sold the horse at a profit of $25 \%$ and the camel at a loss of $20 \%$. Also, he sold both the anlmals at same price.
Sellıng price of horse $=$ Selling price of camel
$\rightarrow$ cost price of horse $+$ Proflt $=$ cost price of camel $+$ horse
$\rightarrow a+25 \%$ of $a=(51250-a)-20 \%$ of $(51250-a)$
$\rightarrow a+0.25 a=(51250-a)-0.2(51250-a)$
$\rightarrow 1.25 a=0.8(51250-a)$
$\rightarrow 1.25 a+0.8 a=0.8(51250)$
$+2.05 a=41000$
$\rightarrow a=20000$
Therefore,
cost price of camel $=\operatorname{Rs}(51250-20000)=$ $Rs. 31250$
Hence, horse is cheaper than camel And cost of price of horse is $Rs 20,000 .$
