10-1.Thermometry, Thermal Expansion and Calorimetry
medium

At what temperature (in $ ^{\circ} C$) a gold ring of diameter $6.230$ $cm$ be heated so that it can be fitted on a wooden bangle of diameter $6.241 \,cm$ ? Both the diameters have been measured at room temperature $\left(27^{\circ} C \right)$. (Given: coefficient of linear thermal expansion of gold $\alpha_{L}=1.4 \times 10^{-5} \,K ^{-1}$ )

A

$125.7$

B

$91.7$

C

$425.7$

D

$152.7$

(JEE MAIN-2022)

Solution

$\Delta \ell=6.241-6.230=0.011 \,cm$

$\Delta \ell=\ell \alpha \Delta \theta$

$0.011=6.230 \times 1.4 \times 10^{-5}(\theta-27)$

$\theta-27=\frac{0.011 \times 10^{5}}{6.230 \times 1.4}$

$\theta \approx 153.11$ nearest is $152.7^{\circ} C$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.