Both the nucleus and the atom of some element | vedclass

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Question

Energy  $E = \frac {hc}{\lambda };$

$\frac{{{\lambda _N}}}{{{\lambda _A}}} = \frac{{{E_A}}}{{{E_N}}}$  

where $E_A$  and $E_

Vedclass · Accepted Answer

$10^{-6}$

Vedclass · Answer

Energy  $E = \frac {hc}{\lambda };$

$\frac{{{\lambda _N}}}{{{\lambda _A}}} = \frac{{{E_A}}}{{{E_N}}}$  

where $E_A$  and $E_N$  are energies of photons from atom and nucleus respectively. $E_N$  is of the order of  $MeV = 10^6\,\,eV$  and $E_A$  in few $eV.$

So  $\frac{{{\lambda _N}}}{{{\lambda _A}}}\, = \,{10^{ - 6}}$

Both the nucleus and the atom of some element are in their respective first excited states. They get de-excited by emitting photons of wavelengths $\lambda _N,\,\lambda _A$ respectively. The ratio $\frac{{{\lambda _N}}}{{{\lambda _A}}}$ is closest to

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