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4-2.Friction
easy
Calculate the maximum acceleration (in $m s ^{-2}$) of a moving car so that a body lying on the floor of the car remains stationary. The coefficient of static friction between the body and the floor is $0.15$ $\left( g =10 m s ^{-2}\right)$.
A$50$
B$1.2$
C$150$
D$1.5$
(NEET-2023)
Solution
$F _{ s }= ma$
$f _{ L }= ma a _{\max }$
$\mu mg = ma _{\max }$
$a _{\text {max }}=\mu g$
$=0.15(10)$
$=1.5\,m / s ^2$
$f _{ L }= ma a _{\max }$
$\mu mg = ma _{\max }$
$a _{\text {max }}=\mu g$
$=0.15(10)$
$=1.5\,m / s ^2$
Standard 11
Physics