Two point charges of 20,μ ,C and 80,μ ,C are 10,cm apart. Where will electric field strength be ze

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1. Electric Charges and Fields

easy

Two point charges of $20\,\mu \,C$ and $80\,\mu \,C$ are $10\,cm$ apart. Where will the electric field strength be zero on the line joining the charges from $20\,\mu \,C$ charge......$m$

$0.1$

$0.04$

$0.033$

$0.33$

Solution

(c) Let neutral point be obtained at a distance $x$ from $20\,\mu \,C$ charge. Hence at neutral point$\frac{{20}}{{{{(x)}^2}}} = \frac{{80}}{{{{(10 – x)}^2}}}$ $==>$ $x = + \,0.033\,m$

Standard 12

Physics

Diagram shows symmetrically placed rectangular insulators with uniformly charged distributions of equal magnitude. At the origin, the net field net ${\vec E_{net}}$ is :-

medium

In the given figure distance of the point from $A$ where the electric field is zero is……$cm$

medium

Select the correct statement : (Only force on a particle is due to electric field)

easy

For what type of charge distribution, electric field can be obtained by using Coulomb’s law and superposition principle ?

medium

Whose result the whole electrostatic is ?

medium

Two point charges of $20\,\mu \,C$ and $80\,\mu \,C$ are $10\,cm$ apart. Where will the electric field strength be zero on the line joining the charges from $20\,\mu \,C$ charge......$m$

Solution

Similar Questions

Diagram shows symmetrically placed rectangular insulators with uniformly charged distributions of equal magnitude. At the origin, the net field net ${\vec E_{net}}$ is :-

In the given figure distance of the point from $A$ where the electric field is zero is……$cm$

Select the correct statement : (Only force on a particle is due to electric field)

For what type of charge distribution, electric field can be obtained by using Coulomb’s law and superposition principle ?

Whose result the whole electrostatic is ?

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