Two point charges of 20,mu ,C and 80,mu ,C ar | vedclass

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Question

(c) Let neutral point be obtained at a distance $x$ from $20\,\mu \,C$ charge. Hence at neutral point$\frac{{20}}{{{{(x)}^2}}} = \frac{{80}}{{{{(10 -

Vedclass · Accepted Answer

$0.033$

Vedclass · Answer

(c) Let neutral point be obtained at a distance $x$ from $20\,\mu \,C$ charge. Hence at neutral point$\frac{{20}}{{{{(x)}^2}}} = \frac{{80}}{{{{(10 - x)}^2}}}$ $==>$ $x =  + \,0.033\,m$

Two point charges of $20\,\mu \,C$ and $80\,\mu \,C$ are $10\,cm$ apart. Where will the electric field strength be zero on the line joining the charges from $20\,\mu \,C$ charge......$m$

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