Coefficient of x^6 in the binomial expansion& | vedclass

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Question

$\left(\frac{4 x^{2}}{3}-\frac{3}{2 x}\right)^{9}$

$T_{r+1}={ }^{9} C_{r}\left(\frac{4 x^{2}}{3}\right)^{9-f}\left(-\frac{3}{2 x}\right)^{r}$

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Vedclass · Accepted Answer

$2688$

Vedclass · Answer

$\left(\frac{4 x^{2}}{3}-\frac{3}{2 x}ight)^{9}$

$T_{r+1}={ }^{9} C_{r}\left(\frac{4 x^{2}}{3}ight)^{9-f}\left(-\frac{3}{2 x}ight)^{r}$

Power of $x=2(9-r)+(-1) r$

$\quad=18-3 r=6$

$\Rightarrow 3 r=18-6=12 \Rightarrow r=4$

Coefficient ${ }^{9} C _{4}\left(\frac{4}{3}ight)^{9-4}\left(\frac{-3}{2}ight)^{4}$

$=\frac{9 	imes 8 	imes 7 	imes 6}{1.2 .3 .4}\left(\frac{4}{3}ight)^{5}\left(\frac{3}{2}ight)^{4}$

$=9 	imes 2 	imes 7 	imes \frac{2^{10} 	imes 3^{4}}{3^{5} 	imes 2^{4}}$

$=21 	imes 2^{7}=2688$

Coefficient of $x^6$ in the binomial expansion ${\left( {\frac{{4{x^2}}}{3}\; - \;\frac{3}{{2x}}} \right)^9}$ is

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