- Home
- Standard 12
- Physics
2. Electric Potential and Capacitance
medium
Concentric metallic hollow spheres of radii $R$ and $4 R$ hold charges $Q _{1}$ and $Q _{2}$ respectively. Given that surface charge densities of the concentric spheres are equal, the potential difference $V ( R )- V (4 R )$ is
A
$\frac{3 Q_{1}}{16 \pi \varepsilon_{0} R}$
B
$\frac{ Q _{2}}{4 \pi \varepsilon_{0} R }$
C
$\frac{3 Q _{1}}{4 \pi \varepsilon_{0} R }$
D
$\frac{3 Q _{2}}{4 \pi \varepsilon_{0} R }$
(JEE MAIN-2020)
Solution
$E =\frac{ KQ _{1}}{ r ^{2}}$
$\Delta V =\int_{ R }^{4 R } E dr =\frac{3 KQ _{1}}{4 R }$
Standard 12
Physics
