6.Permutation and Combination
hard

Consider a class of $5$ girls and $7$ boys. The number of different teams consisting of $2$ girls and $3$ boys that can be formed from this class, if there are two specific boys $A$ and $B$, who refuse to be the members of the same team, is

A

$500$

B

$200$

C

$300$

D

$350$

(JEE MAIN-2019)

Solution

Number of ways $=$ Total number of ways without restriction $-$ When two specific boys are in team without any restriction, total number of ways of forming team is  $^7{C_3}{ \times ^5}{C_2} = 350$ If two specific boys $B_1,B_2$ are in same team then total number of ways of forming team equals to $^5{C_1}{ \times ^5}{C_2} = 50$ ways total ways $=350-50=300$ ways

Standard 11
Mathematics

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