Consider the following statements :
$A$ : Rishi is a judge.
$B$ : Rishi is honest.
$C$ : Rishi is not arrogant.
The negation of the statement "if Rishi is a judge and he is not arrogant, then he is honest" is
$B \rightarrow( A \vee C )$
$(\sim B ) \wedge( A \wedge C )$
$B \rightarrow((\sim A ) \vee(\sim C ))$
$B \rightarrow( A \wedge C )$
Let the operations $*, \odot \in\{\wedge, \vee\}$. If $( p * q ) \odot( p \odot \sim q )$ is a tautology, then the ordered pair $(*, \odot)$ is.
Consider
Statement $-1 :$$\left( {p \wedge \sim q} \right) \wedge \left( { \sim p \wedge q} \right)$ is a fallacy.
Statement $-2 :$$(p \rightarrow q) \leftrightarrow ( \sim q \rightarrow \sim p )$ is a tautology.
$(p\; \wedge \sim q) \wedge (\sim p \vee q)$ is
Contrapositive of the statement 'If two numbers are not equal, then their squares are not equal', is
Which of the following Boolean expressions is not a tautology ?