convert 1; newton (SI unit of force) into dyn | vedclass

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Question

The dimensional equation of force is $[F]=\left[M^{1} L^{1} T^{-2}\right]$

if $n_{1}, u_{1}$, and $n_{2}, u_{2}$ corresponds to $SI$ and $CGS$ unit

Vedclass · Accepted Answer

$10^5$

Vedclass · Answer

The dimensional equation of force is $[F]=\left[M^{1} L^{1} T^{-2}ight]$

if $n_{1}, u_{1}$, and $n_{2}, u_{2}$ corresponds to $SI$ and $CGS$ units respectively, then $n_{2}=n_{1}\left[\frac{M_{1}}{M_{2}}ight]^{1}\left[\frac{L_{1}}{L_{2}}ight]^{1}\left[\frac{T_{1}}{T_{2}}ight]^{2}$$=1\left[\frac{k g}{g}ight]\left[\frac{m}{c m}ight]\left[\frac{s}{s}ight]^{-2}=1 	imes 1000 	imes 100 	imes 1=10^{5}$

$	herefore 1$ newton $=10^{5}$ dyne.

convert $1\; newton$ ($SI$ unit of force) into $dyne$ ($CGS$ unit of force)

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