Define dimensional formula and dimensional equation by using suitable example.
Dimensional formulae : The expression which shows how and which of the base quantity represent the dimensions of a physical quantity.
Example :
Dimensional formulae of volume is $\left[\mathrm{M}^{0} \mathrm{~L}^{3} \mathrm{~T}^{0}\right]$
Dimensional formula of speed (or velocity) is $\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-1}$
Dimensional formulae of acceleration is $\left[\mathrm{M}^{0} \mathrm{LT}^{-2}\right]$
Dimensional formula of density is $\left[\mathrm{M}^{0} \mathrm{~L}^{-3} \mathrm{~T}^{0}\right]$
Dimensional equation : An equation obtained by equating a physical quantity with its dimensional formula is called dimensional equation of the physical quantity.
Example :
Volume $[\mathrm{V}]=\left[\mathrm{M}^{0} \mathrm{~L}^{3} \mathrm{~T}^{0}\right]$
Speed or Velocity $[v]=\left[\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-1}\right]$
Force $[\mathrm{F}]=\left[\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-2}\right]$
Density $[\rho]$ (Density) $[d]=\left[\mathrm{M}^{1} \mathrm{~L}^{-3} \mathrm{~T}^{0}\right]$
The dimension of stopping potential $\mathrm{V}_{0}$ in photoelectric effect in units of Planck's constant $h$, speed of light $c$ and Gravitational constant $G$ and ampere $A$ is
Consider the following equation of Bernouilli’s theorem. $P + \frac{1}{2}\rho {V^2} + \rho gh = K$ (constant)The dimensions of $K/P$ are same as that of which of the following
If $\mathrm{E}$ and $\mathrm{G}$ respectively denote energy and gravitational constant, then $\frac{\mathrm{E}}{\mathrm{G}}$ has the dimensions of :
The dimension of $P = \frac{{{B^2}{l^2}}}{m}$ is
where $B=$ magnetic field, $l=$ length, $m =$ mass
The dimensions of ${\left( {{\mu _0}{\varepsilon _0}} \right)^{ - \frac{1}{2}}}$ are