Difference between nth and (n +1)^{th} Bohr’s radius of ‘H’ atom is equal to it&rs

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12.Atoms

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Difference between nth and $(n +1)^{th}$ Bohr’s radius of $‘H’$ atom is equal to it’s $(n-1)^{th}$ Bohr’s radius. the value of $n$ is:

A

$1$

B

$2$

C

$3$

D

$4$

Solution

$(n+1)^{2}-n^{2}=(n-1)^{2}$

$\Rightarrow 1+2 n=n^{2}+1-2 n$

$\Rightarrow n^{2}=4 n$

$\Rightarrow n=4$

Standard 12

Physics

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