Gujarati
Hindi
1.Relation and Function
normal

Domain of the function $f(x) =$ $\frac{1}{{\sqrt {\ln \,{{\cot }^{ - 1}}x} }}$ is

A

$(cot\,\,1 , \infty )$

B

$R - \{cot\,\,1\}$

C

$(- \infty ,0) \cup (0,cot\,\,1)$

D

$(- \infty , cot\,\,1)$

Solution

ln $(cot^{-1}x) > 0$
$cot^{-1}x > 1$
$x < cot \,\,1$
$\therefore$  domain $(- \infty , cot\,\,1)$ 

Standard 12
Mathematics

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