- Home
- Standard 12
- Mathematics
1.Relation and Function
normal
Domain of the function $f(x) =$ $\frac{1}{{\sqrt {\ln \,{{\cot }^{ - 1}}x} }}$ is
A
$(cot\,\,1 , \infty )$
B
$R - \{cot\,\,1\}$
C
$(- \infty ,0) \cup (0,cot\,\,1)$
D
$(- \infty , cot\,\,1)$
Solution
ln $(cot^{-1}x) > 0$
$cot^{-1}x > 1$
$x < cot \,\,1$
$\therefore$ domain $(- \infty , cot\,\,1)$
Standard 12
Mathematics
Similar Questions
normal