Equation of the tangent to the circle ${x^2} + {y^2} = {a^2}$ which is perpendicular to the straight line $y = mx + c$ is
Equation of the tangent to the circle ${x^2} + {y^2} = {a^2}$ which is perpendicular to the straight line $y = mx + c$ is
- A
$y = - \frac{x}{m} \pm a\sqrt {1 + {m^2}} $
- B
$x + my = \pm {\rm{ }}a{\rm{ }}\sqrt {1 + {m^2}} $
- C
$x + my = \pm a\sqrt {1 + {{(1/m)}^2}} $
- D
$x - my = \pm a\sqrt {1 + {m^2}} $
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