Explain uncertainty or error in given measurement by suitable example.
$(1)$ Length and breadth of a thin rectangular plate is $l=16.2 \mathrm{~cm}$ and breadth $b=10.1 \mathrm{~cm}$ Least count of meterscale is $0.1 \mathrm{~cm}$ hence absolute error in measurement should be $0.1 \mathrm{~cm}$.
$l=(16.2 \pm 0.1) \mathrm{cm}$
$b=(10.1 \pm 0.1) \mathrm{cm}$
$\%$ error in measurement of length,
$l=(16.2 \pm 0.6 \%) \mathrm{cm}$
$\%$ error in measurement of breadth,
$b=(10.1 \pm 1 \%) \mathrm{cm}$
Area of rectangular plate,
$\mathrm{A} =l b$
$=16.2 \times 10.1=163.62 \mathrm{~cm}^{2}$
$\%$ error in $\mathrm{A}$ :
$=\frac{\Delta \mathrm{A}}{\mathrm{A}} \times 100=\frac{\Delta l}{l} \times 100+\frac{\Delta b}{b} \times 100$
$=(0.6 \%+1 \%)=1.6 \%$
$\Delta \mathrm{A} =\frac{1.6 \times 163.62}{100}=2.6$
Area : $\mathrm{A}=(163.62 \pm 2.6) \mathrm{cm}^{2}$
Here, minimum significant digit are $3$ hence area should be represented as, $\mathrm{A} \approx 163 \pm 3 \mathrm{~cm}^{2}$
$\therefore$ Error in measurement of area of plate is $3 \mathrm{~cm}^{2}$.
$(2)$ If a set of experimental data is specified to ' $n$ ' significant figures, a result obtained by combining the data will also be valid to ' $n$ ' significant figures.
However, if data is subtracted the number of significant figures can be reduced. For example,
$12.9 \mathrm{~g}-7.06 \mathrm{~g}=5.84 \mathrm{~g}$
Here, there are $3$ significant digits. But in subtraction digit after decimal point are considered hence this will be represented as $5.8 \mathrm{~g}$.
If the length of rod $A$ is $3.25 \pm 0.01 \,cm$ and that of $B$ is $4.19 \pm 0.01\, cm $ then the rod $B$ is longer than rod $A$ by
A physical quantity $A$ is related to four observable $a,b,c$ and $d$ as follows, $A = \frac{{{a^2}{b^3}}}{{c\sqrt d }}$, the percentage errors of measurement in $a,b,c$ and $d$ are $1\%,3\%,2\% $ and $2\% $ respectively. What is the percentage error in the quantity $A$ ......... $\%$
The period of oscillation of a simple pendulum is $T =2 \pi \sqrt{\frac{ L }{ g }} .$ Measured value of $ L $ is $1.0\, m$ from meter scale having a minimum division of $1 \,mm$ and time of one complete oscillation is $1.95\, s$ measured from stopwatch of $0.01 \,s$ resolution. The percentage error in the determination of $g$ will be ..... $\%.$
Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$
Assertion $A$ : A spherical body of radius $(5 \pm 0.1)$ $mm$ having a particular density is falling through a liquid of constant density. The percentage error in the calculation of its terminal velocity is $4\,\%$.
Reason $R$ : The terminal velocity of the spherical body falling through the liquid is inversely proportional to its radius.
In the light of the above statements, choose the correct answer from the options given below on :
A cylindrical wire of mass $(0.4 \pm 0.01)\,g$ has length $(8 \pm 0.04)\,cm$ and radius $(6 \pm 0.03)\,mm$.The maximum error in its density will be $......\,\%$