Find sets $A, B$ and $C$ such that $A \cap B, B \cap C$ and $A \cap C$ are non-empty sets and $A \cap B \cap C=\varnothing$
Let $A=\{0,1\}, B=\{1,2\},$ and $C=\{2,0\}$
Accordingly, $A \cap B=\{1\}, B \cap C=\{2\},$ and $A \cap C=\{0\}$
$\therefore A \cap B, B \cap C,$ and $A \cap C$ are non-empty.
Howerer, $A \cap B \cap C=\varnothing$
If $A$ and $B$ are any two sets, then $A \cap (A \cup B)$ is equal to
If $n(A) = 3$ and $n(B) = 6$ and $A \subseteq B$. Then the number of elements in $A \cap B$ is equal to
If $A \cap B = B$, then
Let $A$ and $B$ be two sets in the universal set. Then $A - B$ equals
Consider the following relations :
$(1) \,\,\,A - B = A - (A \cap B)$
$(2) \,\,\,A = (A \cap B) \cup (A - B)$
$(3) \,\,\,A - (B \cup C) = (A - B) \cup (A - C)$
which of these is/are correct