Find sets $A, B$ and $C$ such that $A \cap B, B \cap C$ and $A \cap C$ are non-empty sets and $A \cap B \cap C=\varnothing$
Let $A=\{0,1\}, B=\{1,2\},$ and $C=\{2,0\}$
Accordingly, $A \cap B=\{1\}, B \cap C=\{2\},$ and $A \cap C=\{0\}$
$\therefore A \cap B, B \cap C,$ and $A \cap C$ are non-empty.
Howerer, $A \cap B \cap C=\varnothing$
If $X$ and $Y$ are two sets such that $X \cup Y$ has $18$ elements, $X$ has $8$ elements and $Y$ has $15$ elements ; how many elements does $X \cap Y$ have?
If $X=\{a, b, c, d\}$ and $Y=\{f, b, d, g\},$ find
$X \cap Y$
If $A, B$ and $C$ are any three sets, then $A - (B \cap C)$ is equal to
If $A=\{3,5,7,9,11\}, B=\{7,9,11,13\}, C=\{11,13,15\}$ and $D=\{15,17\} ;$ find
$A \cap C \cap D$
Which of the following pairs of sets are disjoint
$\{a, e, i, o, u\}$ and $\{c, d, e, f\}$