If $A = \{ x:x$ is a natural number $\} ,B = \{ x:x$ is an even natural number $\} $ $C = \{ x:x$ is an odd natural number $\} $ and $D = \{ x:x$ is a prime number $\} ,$ find
$B \cap D$
$A = \{ x:x$ is a natural number $\} = \{ 1,2,3,4,5 \ldots \} $
$B = \{ x:x$ is an even natural number $\} = \{ 2,4,6,8 \ldots \} $
$C = \{ x:x$ is an odd natural number $\} = \{ 1,3,5,7,9 \ldots \} $
$D = \{ x:x$ is a primenumber $\} = \{ 2,3,5,7 \ldots \}$
$B \cap D=\{2\}$
If $A$ and $B$ are two sets, then $A \cup B = A \cap B$ iff
If $A =$ [$x:x$ is a multiple of $3$] and $B =$ [$x:x$ is a multiple of $5$], then $A -B$ is ($\bar A$ means complement of $A$)
If $A=\{3,5,7,9,11\}, B=\{7,9,11,13\}, C=\{11,13,15\}$ and $D=\{15,17\} ;$ find
$A \cap \left( {B \cup C} \right)$
Let $A = \{a, b, c\}, B = \{b, c, d\}, C = \{a, b, d, e\},$ then $A \cap (B \cup C)$ is
Find the union of each of the following pairs of sets :
$A = \{ x:x$ is a natural number and multiple of $3\} $
$B = \{ x:x$ is a natural number less than $6\} $